[HackerRank] Jumping on the Clouds _Java8

 

 

Problem

 

 

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Solution

 

Max distance that we can move at a time is 2.

Look at the index value larger than current position by 2.

If the value is 0, move 2 times and add a jump.

If the value is 1, move just one time and add a jump.

 

(If we are at a position where only one number is left in the array, it is not possible to move up 2 times... so just add one jump and end the loop.)

 

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.function.*;
import java.util.regex.*;
import java.util.stream.*;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;

class Result {

    /*
     * Complete the 'jumpingOnClouds' function below.
     *
     * The function is expected to return an INTEGER.
     * The function accepts INTEGER_ARRAY c as parameter.
     */

    public static int jumpingOnClouds(List<Integer> c) {
    int jump = 0;
    int currPos = 0;
    
    while(true){
    if(currPos == c.size()-1)
        break;
    if(currPos == c.size()-2 || c.get(currPos+2) == 1)
        currPos++;
    else
        currPos = currPos+2;
    jump++;
    }
    
    return jump;

    }

}

public class Solution {
    public static void main(String[] args) throws IOException {
        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
        BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));

        int n = Integer.parseInt(bufferedReader.readLine().trim());

        List<Integer> c = Stream.of(bufferedReader.readLine().replaceAll("\\s+$", "").split(" "))
            .map(Integer::parseInt)
            .collect(toList());

        int result = Result.jumpingOnClouds(c);

        bufferedWriter.write(String.valueOf(result));
        bufferedWriter.newLine();

        bufferedReader.close();
        bufferedWriter.close();
    }
}